Tutorial 2 Q | Pressure | Density

Multiply this to the given shearing stress. shearing force = (4 x 10^8 N/m²)(4.15 m²) shearing force = 1.66 x 10^9 N. b. Determine the surface area of the cylinder that is made upon boring the hole in steel plate....Stress In Steel Exceeds About 4.00 108 N/m2, The Steel Ruptures. (a) Determine The Shearing Force Necessary To Shear A Steel Bolt 1.20 Cm In Diameter. exceeds about 4.00 108 N/m2, the steel ruptures. (a) Determine the shearing force necessary to shear a steel bolt 1.20 cm in diameter.If the shear stress in steel exceeds about 4.80 108 N/m2, the steel ruptures.(a) Determine the shearing force necessary toshear a steel bolt 1.10 070. M I. -12 points My Notes Ask Your Teacher 4. Assume that if the shear stress in steel exceeds about 4.00 x 108 N/m2, the steel ruptures. (a)...Problem 104 A hollow steel tube with an inside diameter of 100 mm must carry a tensile load of 400 kN. Determine the outside diameter of the tube if the stress is limited to 120 MN/m2.Determine the shearing force necessary to (a) shear a steel bolt 1.00 cm in diameter and (b) punch a 1.00-cm-diameter hole in a steel plate 0.500 cm thick.

Solved: Assume That If The Shear Stress In Steel Exceeds A...

Determine the shearing force necessary to (a) Shear a steel bolt 1.00 cm in diameter and (b) Punch a 1.00-cm-diameter hole in a steel plate 0.500 cm thick. buy a solution for 0.5$.Determine the shearing force necessary to a sheal a steel bolt 1.00 cm in diameter and b punch a 1.00 cm diameter hole in a steel plate 0.500 cm thick. Question from Class 11 Chapter Properties Of Solids And Fluids. Apne doubts clear karein ab Whatsapp par bhi."If the shear stress in steel exceeds about 4.00 x 10^8 N/m^2, the steel ruptures. Determine the shearing force necessary to (a) shear a steel bolt 1.00 cm in diameter and (b) punch a 1.00 cm diameter hole in a steel plate .500 cm thick. I think I got A right (3.14x10^4, right?), but I'm stuck on B...The shear stress varies from zero in the axis to a maximum at the outside surface of the shaft. The shear stress in a solid circular shaft in a given A moment of 1000 Nm is acting on a solid cylinder shaft with diameter 50 mm (0.05 m) and length 1 m. The shaft is made in steel with modulus of rigidity...

5. Certain stainless steel has a shear stress limit 4.00x108...

If the shear stress is not to exceed 50 MPa, find the power which can be transmitted. 3 - 10 POWER TRANSMITTED BY A SHAFT Problem 8 A solid steel shaft has to transmit 100 kW at 160 RPM. Taking allowable shear stress at 70 Mpa, find the suitable diameter of the shaft.Determine the shearingforce necessary to (a) shear a steel bolt 1.00 cm indiameter and (b) punch a 1.00-cm-diameter hole in asteel plate 0.500 cm thick.(a) Determine the shearing force necessary to shear a steel bolt 1.40 cm in diameter. If the elastic limit of steel is 5.0 multiplied by 108 Pa, determine the minimum diameter a steel wire can have if it is to support a 79 kg circus performer without its elastic limit being exceeded.4.If the shear stress in steel exceeds about 4.10 108 N/m2, the steel ruptures. (a) Determine the she. 5.machanical work=_ X distance.2. If the shear stress in steel exceeds about 4.00 × 108 N/m2, the steel ruptures. If the wire is stretched 0.10 mm, find the magnitude and direction of the force on the tooth. Disregard the width of the tooth, and assume that Young's modulus for stainless steel is 18 × 1010 Pa.

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RE:

Assume that if the shear stress in steel exceeds about 4.00 108 N/m2, the steel ruptures.?

(a) Determine the shearing pressure vital to shear a steel bolt 1.40 cm in diameter.

(b) Determine the shearing drive important to punch a 1.75-cm-diameter hole in a steel plate 0.540 cm thick.

I got the resolution for (a). Now im caught on (b). Please Show Work! Thank you!

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